### Table V. Non-linear dynamics of frame: CPU time for St. Venant-Kirchhoff hyper- elasto-plasticity with total Lagrangian formulation.

in SUMMARY

### Table 1. Computation times and number of unknowns for the elasto-plastic loading and unloading of a tube under internal pressure (v =0*49)

in SUMMARY

### Table V. CPU time for finite deformation elasto-plasticity case.

### Table2 Description of three-dimensional meshes.

"... In PAGE 6: ... In short, we made these meshes havevery small #28and hence many#29 elements along lines that would result in a split into pieces of roughly equal size. Most meshes in Table2 were obtained from tetrahedralization of objects such as an aircraft #0Dap, or of a domain enclosed between two spherical sections. Twoof the meshes in Table 2, #5Csphere 5 quot; and #5Csphere 6 quot;, are surface triangulations of three dimensional objects.... In PAGE 6: ... Most meshes in Table 2 were obtained from tetrahedralization of objects such as an aircraft #0Dap, or of a domain enclosed between two spherical sections. Twoof the meshes in Table2 , #5Csphere 5 quot; and #5Csphere 6 quot;, are surface triangulations of three dimensional objects. Observe that meshes in the test suite are highly graded and irregular, with element sizes that vary by factors larger than 1000 in the L 1 norm.... ..."

### Table 6. Three-dimensional compressible derivatives

1997

"... In PAGE 5: ... In this test, the cost function is a combination of the lift and drag coefficients so that only one adjoint solution is required. The derivatives of the cost with respect to the angle of attack and the Mach number as well as the derivatives with respect to four of the shape parameterization variables are shown in Table6 . As can be seen, the consistency between the derivatives obtained with the ad- joint formulation and finite differences is excellent.... ..."

Cited by 68

### Table 6. Three-dimensional compressible derivatives

1997

"... In PAGE 5: ... In this test, the cost function is a combination of the lift and drag coefficients so that only one adjoint solution is required. The derivatives of the cost with respect to the angle of attack and the Mach number as well as the derivatives with respect to four of the shape parameterization variables are shown in Table6 . As can be seen, the consistency between the derivatives obtained with the ad- joint formulation and finite differences is excellent.... ..."

Cited by 68

### Table 6 shows timings for the solution of the three-dimensional problem

"... In PAGE 22: ...6 14.3 Table6 : Solution times (in seconds) and speedups for the restricted weakly overlap- ping algorithm on the three-dimensional problem (58) (taken from [40]). equations based upon a geometric decomposition of the problem.... ..."

### Table 6 shows timings for the solution of the three-dimensional problem

"... In PAGE 22: ...6 14.3 Table6 : Solution times (in seconds) and speedups for the restricted weakly overlap- ping algorithm on the three-dimensional problem (58) (taken from [40]). equations based upon a geometric decomposition of the problem.... ..."

### Table 1: An example of a three-dimensional table.

1993

"... In PAGE 3: ...Table1 has three categories, D1, D2 and D3; thus, it is a three-dimensional table. The logical relationship among the data items of a table is the association between labels and entries.... In PAGE 3: ... Each entry is associated with one or more sets of labels of di erent categories simultaneously. For example, in Table1 , entry e1 is associated with a set of labels fd11; d21; d311g simultaneously; entry e7 is associated with both fd12; d21; d312g and fd12; d22; d312g simultaneously. The data items and the logical relationship among them provide the logical structure of the table, which is the primary information that a table conveys and which is independent of its format.... In PAGE 6: ... This function guarantees that every entry in E is mapped from at least one ff1; ; fng 2 D1 n. Using this model, Table1 can be abstracted by (3; fD1; D2; D3g; E; ), where D1 = fd11; d12g D2 = fd21; d22; d23g D3 = fd31; d32g d31 = fd311; d312g d11 = d12 = d21 = d22 = d23 = d32 = d311 = d312 = fg E = fe1; e2; e3; e4; e5; e6; e7; e8; e9g (fD1:d11; D2:d21; D3:d31:d311g) = e1; (fD1:d11; D2:d21; D3:d31:d312g) = e2; (fD1:d11; D2:d22; D3:d31:d311g) = e3; (fD1:d11; D2:d22; D3:d31:d312g) = e3; (fD1:d11; D2:d23; D3:d31:d311g) = e4; (fD1:d11; D2:d21; D3:d32g) = e5; (fD1:d11; D2:d22; D3:d32g) = e5; (fD1:d11; D2:d23; D3:d32g) = e5; (fD1:d12; D2:d21; D3:d31:d311g) = e6; (fD1:d12; D2:d21; D3:d31:d312g) = e7; (fD1:d12; D2:d22; D3:d31:d312g) = e7; (fD1:d12; D2:d23; D3:d31:d312g) = e8; (fD1:d12; D2:d21; D3:d32g) = e9; (fD1:d12; D2:d22; D3:d32g) = e9; (fD1:d12; D2:d23; D3:d32g) = e9; 4.2 Basic operators in the tabular model We rst describe the syntax of all basic operators in function form by giving the operator identi ers and the types of their operands and results.... ..."

Cited by 2