### Table 2: The computed eigenvalues z = x0 and z = z 0 , which are the roots of the eigenvalue equation (z; Qi) = 0, for ows driven by a constant inlet ow rate Qi, and quot; = 0:005, = 1. The radial coordinate r signi es the position of the discontinuity in the (steady state) velocity gradient, and P = limt!1 P (t) is the steady state pressure.

"... In PAGE 9: ...4, where we found that for quot; = 0:02 and = 1 the transient ow shows damped oscillations and tends to a steady state for each value of Qi. (Table 1) In Table2 the computed eigenvalues z = x0 and z = z 0 = 0 i are presented for ows driven by a constant inlet ow rate Qi, varying from Qi = 0:18 gt; Qcrit to Qi = 3:0, in case quot; = 0:005, = 1. We observe that for Qi 0:35 and Qi 0:90 all eigenvalues have a negative real part (x0 lt; 0 and Re z 0 lt; 0), whereas for 0:40 Qi 0:80 the eigenvalues z = z 0 have a positive real part (Re z 0 gt; 0).... In PAGE 13: ... The existence is supported by an in fact rather restricted number of numerical examples. In this second part, however, the inference is corroborated by the results of the linearized stability theory, as presented in Table2 and in Figures 1 and 2. For instance, we found here, precisely in correspondence to the result of [1, Sect.... ..."

### Table 1. Negative constants: termination.

2004

"... In PAGE 11: ... Tables 1 and 2 show the e ect of the negative constant method developed in Section 3. In Table1 we prove termination whereas in Table 1 we prove innermost termination. In the columns labelled n we use the natural interpretation for certain function symbols that appear in many example TRSs: 0Z = 0 1Z = 1 2Z = 2 sZ(x) = x + 1 +Z(x; y) = x + y Z(x; y) = xy pZ(x) = x 11 Z(x; y) = x y1 For other function symbols we take linear interpretations fZ(x1; : : : ; xn) = a1x1 + + anxn + b 1 In Tables 1 and 2 we do not x the interpretation of p when 1 is not included in... In PAGE 12: ... Not surprisingly, this method is more suited for proving innermost termination because the method is incompatible with the recent modular re nements of the dependency pair method when proving termination (for non-overlapping TRSs). Comparing the rst (last) three columns in Table 3 with the last three columns in Table1 (Table 2) one might be tempted to conclude that the approach... ..."

Cited by 3

### Table 1: Errors and convergence rates for the x-component of the pressure gradient.

1997

Cited by 13

### Table 2: Errors and convergence rates for the y-component of the pressure gradient.

1997

Cited by 13

### Table 2. Negative constants: innermost termination.

2004

"... In PAGE 12: ... Not surprisingly, this method is more suited for proving innermost termination because the method is incompatible with the recent modular re nements of the dependency pair method when proving termination (for non-overlapping TRSs). Comparing the rst (last) three columns in Table 3 with the last three columns in Table 1 ( Table2 ) one might be tempted to conclude that the approach... ..."

Cited by 3

### Table 1: The computed eigenvalues z = x0 and z = z 0 , which are the roots of the eigenvalue equation (z; Qi) = 0, for ows driven by a constant inlet ow rate Qi, and quot; = 0:02, = 1. The radial coordinate r signi es the position of the discontinuity in the steady state velocity gradient !(r), and P = limt!1 P (t) is the steady state pressure.

"... In PAGE 9: ...13) has three eigenvalues z: one real eigenvalue z = x0 lt; 0, and two complex conjugate eigenvalues z = z 0 := 0 i . In Table1 the computed eigenvalues z = x0 and z = z 0 = 0 i are presented for ows driven by a constant inlet ow rate Qi, varying from Qi = 0:19 gt; Qcrit to Qi = 3:0, in case quot; = 0:02, = 1. In this table also the radial coordinate r at which the steady state velocity gradient !(r) is discontinuous, and the steady state pressure P = limt!1 P (t) are listed; cf.... In PAGE 18: ... In conclusion, our predictions about the dependence of the onset of persistent oscillations on the molecular weight M are in accordance with the observations of Lim and Schowalter [9] listed above. The ow curves in [1], Figures 7 or 13, show a kink at the critical ow rate Qi = Qcrit, independent of ; here Qcrit = 1=6+O( quot;) (see [1], Table1 ). According to the de nition of in (5.... ..."

### Table 1: Parametervalues used to fit SAC to the negative prim- ing data.

1998

Cited by 1

### Table (4.01): Computation showing the coefficients of skin friction (H) and the axial pressure gradient (A).

### Table 1. Arterial pressure responses to lower body negative pressure (n =4) Level _15 mmHg _30 mmHg

2008

"... In PAGE 4: ... This cardio- acceleration was greater during in-flight than during pre- or postflight sessions (P lt;0 05). Arterial pressure changes are given in Table1 . Systolic and diastolic pressures did not change significantly during lower body suction in any session.... ..."