n1 Y = n + 2n n D1 = 1− 2Y n i (21) (22) (23) (24) n D2 = 2 − 3Y n n D3 = 3 − 4Y n where n1, n2, n3, andn4are total number of trigrams with exactly one, two, three, and four counts. Notice that for experiments in this paper, we do not use this approximati (0)

by Thanks to Ries, K
Venue:P || P' ) = −P( w i−2 w i−1 + [logα '( w i−2 ){ P( w | w w i−1 i i−2 w i−1 ) − logα ( w )[log P( w | w i−2 w i−1 )] i i−1 ∑ P( wi wi : C( wi , wi −2wi −1 ) = 0 ) + logα '( w | w i−2 i−2 w i−1 w i−1 )} ) − log P( w | w